Since the Earth is, as we’re TOLD, a Sphere 25,000 miles in circumference… radius 3959 miles, then Pilots traveling for 1 Hour @ a typical cruising speed of 500 mph — to simply MAINTAIN ALTITUDE, would constantly have to adjust their altitude downwards, (to Compensate for the Curvature) and descend on AVERAGE 2,789 Feet EVERY MINUTE !!

.

Now to negotiate “The DROP”, I really don’t care, the plane can: “Barrel Roll”, “Split S”, “Wing-Over”,

“Tail Slide”, “Slow Roll”, “Cuban Eight”, “Falling Leaf”, “Chandelle”, or The Hokey Pokey …

BUT IT MUST DESCEND !!!

.

And EVERYONE ON THE PLANE WILL KNOW IT !!!!

Is this Clear Spherfers ??

.

A. How many miles of “VERTICAL DROP” (Geometric) *MUST BE* negotiated over a distance of 500 Miles on a Ball with a Circumference of 25,000 Miles?

Answer: 31.7 miles

How many Feet are in 31.7 Miles ??

Answer: 167,376 feet

SOOOOO… 167,376 Feet of “VERTICAL DROP“ *MUST BE* Negotiated over 500 Miles on Earth.

1. REAL WORLD: I’m traveling by Commercial Plane from Pittsburgh PA to Atlanta GA for the Super Bowl.

a. Approx. distance: 500 Miles.

.

2. Typical Cruising Speed = 500 mph.

a. 500 Miles Distance at 500 Miles per hour = Travel Time of 1 Hour.

SOOOOOOOOOO….

Question: How many *FEET of VERTICAL DROP PER MINUTE* on AVERAGE needs to be negotiated on my trip…?

b. Total Feet VERTICAL DROP over 500 Miles = 167,376 Feet.

c. Travel Time = 1 Hour.

Simple Calc: 167,376 Feet/60 Minutes.

Answer: 2789.6 Feet “VERTICAL DROP“ Per Minute AVERAGE *MUST BE* negotiated by the Plane on my trip.

Does this ^^^^^^^^^^^^^^^^^^^^^^^^ happen ? NO ???

The Sphere is a Stone Cold Spherytale !! …

.

.

B. How many miles of “VERTICAL DROP” (Geometric) MUST BE negotiated over a distance of 1000 Miles on a Ball with a Circumference of 25,000 Miles?

Answer: 128.3 Miles !!

How many Feet are in 128.3 Miles??

Answer: 677,424 Feet !!

SOOOOO… 677,424 Feet of “VERTICAL DROP“ *MUST BE* Negotiated over 1000 Miles on Earth.

1. REAL WORLD: I’m traveling by Commercial Plane from Pittsburgh PA to Dallas TX.

a. Approx. distance: 1000 Miles.

.

2. Typical Cruising Speed = 500 mph.

a. 1000 Mile Distance at 500 Miles per hour = Travel Time of 2 Hours (120 mins).

SOOOOOOOOOO…

Question: How many *FEET of VERTICAL DROP PER MINUTE* on AVERAGE needs to be negotiated on my trip…?

b. Total Feet “VERTICAL DROP” over 1000 Miles = 677,424 Feet.

c. Travel Time = 2 Hours.

Simple Calc: 677,424 Feet/120 Minutes.

Answer: 5645 Feet “VERTICAL DROP“ (OVER A MILE !!) Per Minute AVERAGE *MUST BE* negotiated by the Plane on my Trip !!!

Modus Tollens:

If *”P“* then *”Q“*.

NOT *”Q“*.

Therefore, NOT *”P“*.

If Commercial Planes travel at 500 mph for 2hrs (1000 Miles) over a sphere with a radius of 3959 miles ( “P“ ) it would then have to descend/negotiate 128.3 miles of vertical drop over the course of its journey ( “Q“ ).

Commercial Planes DO NOT descend 128.3 miles while traveling at 500 mph for 2hrs (i.e., They Fly LEVEL). ( *“NOT Q“* )

Therefore, the Earth is NOT A SPHERE. ( *“Therefore NOT P“* )

.

.

Alice in Wonderland is more tenable than the BallTARD Spinning Space Monkey Religion.

The Prosecution Rests.

Simple.

You live in a Fairytale.

The End.